The ball

The ball has a radius of 2m. What percentage of the surface and volume is another sphere whose radius is 20% larger?

Correct answer:

p1 =  44 %
p2 =  72.8 %

Step-by-step explanation:

r1=2 m r2=(1+20/100) r1=(1+20/100) 2=125=2.4  S1=4π r12=4 3.1416 2250.2655 m2 S2=4π r22=4 3.1416 2.4272.3823 m2  p1=100 S2S1S1=100 72.382350.265550.2655=44   Verifying Solution:  q=1.2 p11=100 (q21)=100 (1.221)=44 % p1=p11=44%
V1=43 π r13=43 3.1416 2333.5103 m3 V2=43 π r23=43 3.1416 2.4357.9058 m3  p2=100 V2V1V1=100 57.905833.510333.5103=3645=72.8   Verifying Solution:  p21=100 (q31)=100 (1.231)=3645=72.8 % p2=p21=3645%=72.8%



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