The ball

The ball has a radius of 2m. What percentage of the surface and volume is another sphere whose radius is 20% larger?

Correct answer:

p1 =  44 %
p2 =  72.8 %

Step-by-step explanation:

r1=2 m r2=(1+20/100) r1=(1+20/100) 2=512=2.4  S1=4π r12=4 3.1416 2250.2655 m2 S2=4π r22=4 3.1416 2.4272.3823 m2  p1=100 S1S2S1=100 50.265572.382350.2655=44=44%   Verifying Solution:  q=1.2 p11=100 (q21)=100 (1.221)=44 % p1 = p11
V1=34 π r13=34 3.1416 2333.5103 m3 V2=34 π r23=34 3.1416 2.4357.9058 m3  p2=100 V1V2V1=100 33.510357.905833.5103=5364=72.8=5364%=72.8%   Verifying Solution:  p21=100 (q31)=100 (1.231)=5364=72.8 % p2 = p21



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