The chord

Calculate a chord length which the distance from the center of the circle (S, 6 cm) equals 3 cm.

Result

t =  10.392 cm

Solution:

r2=32+(t/2)2 t=2r2−32 t=262−32=10.392 cmr^2 = 3^2 + (t/2)^2 \ \\ t = 2 \sqrt{ r^2-3^2} \ \\ t = 2 \sqrt{ 6^2-3^2} = 10.392 \ \text{cm}

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