Chord 2

Point A has distance 13 cm from the center of the circle with radius r = 5 cm. Calculate the length of the chord connecting the points T1 and T2 of contact of tangents led from point A to the circle.

Correct result:

x =  9.23 cm

Solution:

$$\begin{gathered} a=5cm \\ c=13cm \\ {b}^2=13^2-5^2 \\ b=12cm \\ {S}_1=S_2 \\ ab\mathrm{/}2=cv\mathrm{/}2 \\ ab\mathrm{/}c=v \\ v=5\cdot 12\mathrm{/}13=4.62cm \\ x=2v=9.23\text{ cm} \end{gathered}$$

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