# Chord 2

Point A has distance 13 cm from the center of the circle with radius r = 5 cm. Calculate the length of the chord connecting the points T1 and T2 of contact of tangents led from point A to the circle.

Result

x =  9.23 cm

#### Solution:

$a = 5 \ cm \ \\ c = 13 \ cm \ \\ b^2 = 13^2 - 5^2 \ \\ b = 12 \ cm \ \\ S_1 = S_2 \ \\ ab/2 = c v / 2 \ \\ ab / c = v \ \\ v = 5 \cdot 12 /13 = 4.62 \ cm \ \\ \ \\ x = 2 v = 9.23 \ \text{ cm }$

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