Solutions

How much 60% solution and how much 35% solution is needed to create 100 l of 40% solution?

Correct result:

A =  20 l
B =  80 l

Solution:

$$\begin{gathered} p_1=60\mathrm{\%}={\displaystyle \frac{60}{100}}=0.6 \\ {p}_2=35\mathrm{\%}={\displaystyle \frac{35}{100}}=0.35 \\ {p}_3=40\mathrm{\%}={\displaystyle \frac{40}{100}}=0.4 \\ V=100\text{ l } \\ A+B=V \\ A\cdot p_1+B\cdot p_2=V\cdot p_3 \\ A+B=100 \\ A\cdot 0.6+B\cdot 0.35=100\cdot 0.4 \\ A+B=100 \\ 0.6A+0.35B=40 \\ A=20=20\text{ l } \\ B=80 \end{gathered}$$

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