Velocity ratio

Determine the ratio at which the fluid velocity in different parts of the pipeline (one part has a diameter of 5 cm and the other has a diameter of 3 cm), when you know that at every point of the liquid is the product of the area of tube [S] and the fluid velocity [v] the same.

Result

v1:v2 =  0.36

Solution:

v1:v2=(3 3)/(5 5)=925=0.36v_1:v_2=(3 \cdot \ 3)/(5 \cdot \ 5) = \dfrac{ 9 }{ 25 } = 0.36



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