Milk package

Milk is sold in a box with dimensions of 9.5 cm; 16.5 cm and 6.5 cm. Determine the maximum amount of milk that can fit into a box. Coating thickness is negligible.

Result

V =  1.019 l

Solution:

a=9.5/10=1920=0.95 dm b=16.5/10=3320=1.65 dm c=6.5/10=1320=0.65 dm 1 l=1 dm3 V=a⋅ b⋅ c=0.95⋅ 1.65⋅ 0.65≐1.0189=1.019  l a = 9.5 / 10 = \dfrac{ 19 }{ 20 } = 0.95 \ dm \ \\ b = 16.5 / 10 = \dfrac{ 33 }{ 20 } = 1.65 \ dm \ \\ c = 6.5 / 10 = \dfrac{ 13 }{ 20 } = 0.65 \ dm \ \\ 1 \ l = 1 \ dm^3 \ \\ V = a \cdot \ b \cdot \ c = 0.95 \cdot \ 1.65 \cdot \ 0.65 \doteq 1.0189 = 1.019 \ \text{ l }

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