Machine tool transport

They were to dispatch and transport 35 machine tools of two types with a total weight of 16.54 tons from the plant. The machine of the first type weighed 420 kg. The second was 80 kilograms heavier. How many machines of the first and second kind did they ship?

Final Answer:

a =  12
b =  23

Step-by-step explanation:

$$\begin{gathered} m_1=420\text{kg} \\ {m}_2=m_1+80=420+80=500\text{kg} \\ m=16.54\text{t}\to \text{kg}=16.54\cdot 1000\text{kg}=16540\text{kg} \\ a+b=35 \\ m=m_1\cdot a+m_2\cdot b \\ 16540=420\cdot a+500\cdot b \\ a+b=35 \\ 420a+500b=16540 \\ Pivot:Row1\leftrightarrow Row2 \\ Row2-\frac{1}{420}\cdot Row1\to Row2 \\ -0.19b=-4.38 \\ b=\frac{-4.38095238}{-0.19047619}=23 \\ a=\frac{16540-500b}{420}=\frac{16540-500\cdot 23}{420}=12 \\ a=12 \\ b=23 \end{gathered}$$

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