Inclined plane

On the inclined plane with an angle of inclination of 30 ° we will put body (fixed point) with mass 2 kg. Determine the acceleration of the body motion on an inclined plane.

Result

a =  4.91 m/s2

Solution:

g=9.81 m/s2 m=2 kg  Fn=Gcos30 Ff=Gsin30  Ff=mgsin30  a=Ff/m=gsin30=9.81sin30=4.91 m/s2 g = 9.81 \ m/s^2 \ \\ m = 2 \ kg \ \\ \ \\ F_n = G \cos 30^\circ \ \\ F_f = G \sin 30^\circ \ \\ \ \\ F_f = mg \sin 30^\circ \ \\ \ \\ a = F_f/m = g \sin 30^\circ = 9.81 \cdot \sin 30^\circ = 4.91 \ m/s^2 \ \\



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