Inclined plane

On the inclined plane with an inclination angle of 30°, we will put the body (fixed point) with mass 9 kg. Determine the acceleration of the body motion on an inclined plane.

Correct answer:

a =  4.91 m/s²

Step-by-step explanation:

$$\begin{gathered} m=9\text{kg} \\ g=9.81{\text{m/s}}^2 \\ \alpha =30{}^{\circ } \\ G=m\cdot g=9\cdot 9.81=\frac{8829}{100}=88.29\text{N} \\ {F}_n=G\cdot \cos \alpha =G\cdot \cos 30°=88.29\cdot \cos 30°=88.29\cdot 0.866025=76.46138\text{N} \\ {F}_p=G\cdot \sin \alpha =G\cdot \sin 30°=88.29\cdot \sin 30°=88.29\cdot 0.5=44.145\text{N} \\ {F}_p=ma \\ a=F_p/m=44.145/9=4.91{\text{m/s}}^2 \end{gathered}$$

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