The cube

The cube has a surface area of 216 dm2. Calculate:
a) the content of one wall,
b) edge length,
c) cube volume.

Correct result:

S1 =  36 dm2
a =  6 dm
V =  216 dm3

Solution:

S=216 dm2  S1=S/6=216/6=36 dm2S=216 \ \text{dm}^2 \ \\ \ \\ S_{1}=S/6=216/6=36 \ \text{dm}^2
S1=a2  a=S1=36=6 dmS_{1}=a^2 \ \\ \ \\ a=\sqrt{ S_{1} }=\sqrt{ 36 }=6 \ \text{dm}
V=a3=63=216 dm3V=a^3=6^3=216 \ \text{dm}^3

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