Summands

We want to split the number 110 into three summands so that the first and the second summand are in the ratio 4: 5, and the third with the first are in ratio 7: 3. Calculate the smallest of the summands.

Correct result:

a =  24
b =  30
c =  56

Solution:

a+b+c=110
a=4/5•b
c=7/3•a

a+b+c = 110
5a-4b = 0
7a-3c = 0

a = 24
b = 30
c = 56

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