Motorcyclist 26141

The passenger car left at 7:00 and was heading east at a speed of 60km/h. A motorcyclist left the same place and headed north at 40 km/h. What will be their air distance at ten o'clock?

Correct answer:

x =  216.3331 km

Step-by-step explanation:

t1=7.00 h t2=10.00 h  T=t2t1=107=3 h  v1=60 km/h v2=40 km/h  v1  v2  v2 = v12 + v22  v=v12+v22=602+402=20 13 km/h72.111 km/h  x=v T=72.111 3=60 13=216.3331 km

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