# Word

What is the probability that a random word composed of chars E, Y, G, E, R, O, M, T will be the GEOMETRY?

Result

p =  0 %

#### Solution:

$n_{ 1 } = 1 \cdot \ 2! = 2 \ \\ n_{ 2 } = 8! = 40320 \ \\ p = 100 \cdot \ \dfrac{ n_{ 1 } }{ n_{ 2 } } = 100 \cdot \ \dfrac{ 2 }{ 40320 } = \dfrac{ 5 }{ 1008 } \doteq 0.005 = 0 \%$

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