Acute triangle

In the acute triangle KLM, V is the intersection of its heights and X is the heel of height to the side KL. The axis of the angle XVL is parallel to the side LM and the angle MKL is 70°. What size are the KLM and KML angles?

Correct result:

KLM =  55 °
KML =  55 °

Solution:

$\mathrm{\angle }KML=180-\mathrm{\angle }MKL-\mathrm{\angle }KLM=180-70-55=5{5}^{\circ }$

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