Acute triangle

In the acute triangle KLM, V is the intersection of its heights and X is the heel of height to the side KL. The axis of the angle XVL is parallel to the side LM and the angle MKL is 70°. What size are the KLM and KML angles?

Correct result:

KLM =  55 °
KML =  55 °

Solution:

MKL=70 MKL+KLM+KML=180  δ=90KLM  KMX=90MKL=9070=20 2δ=90KMX δ=(90KMX)/2=(9020)/2=35  KLM=90δ=9035=55
KML=180MKLKLM=1807055=55



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