KLM triangle

Find the length of the sides of the triangle KLM if m = 5cm height to m = 4.5 cm and size MKL angle is 70 degrees.

Result

k =  5.617 cm

Solution:

m=5 cm v1=4.5 cm K=70 ∘  m1=v1/tan⁡(K∘→ rad)=v1/tan⁡(K∘⋅ π180 )=4.5/tan⁡(70∘⋅ 3.1415926180 )=1.63787 m2=m−m1=5−1.6379≐3.3621 cm  k=v12+m22=4.52+3.36212≐5.6173≐5.617 cmm=5 \ \text{cm} \ \\ v_{ 1 }=4.5 \ \text{cm} \ \\ K=70 \ ^\circ \ \\ \ \\ m_{ 1 }=v_{ 1 } / \tan( K ^\circ \rightarrow\ \text{rad})=v_{ 1 } / \tan( K ^\circ \cdot \ \dfrac{ \pi }{ 180 } \ )=4.5 / \tan( 70 ^\circ \cdot \ \dfrac{ 3.1415926 }{ 180 } \ )=1.63787 \ \\ m_{ 2 }=m - m_{ 1 }=5 - 1.6379 \doteq 3.3621 \ \text{cm} \ \\ \ \\ k=\sqrt{ v_{ 1 }^2 + m_{ 2 }^2 }=\sqrt{ 4.5^2 + 3.3621^2 } \doteq 5.6173 \doteq 5.617 \ \text{cm}

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