Three

Three buses follow the same circular route. The first driver is the slowest because he has many stops, and it takes him 90 minutes to cross the route. The second driver will pass the circuit in 1 hour. The third driver has the fewest stops, and the circuit passes in 45 minutes. When will everyone meet when they leave at the same time in the morning?

Correct answer:

t =  180 min

Step-by-step explanation:

a=90 min b=1 h min=1 60  min=60 min c=45 min  90=2325 60=2235 45=325 LCM(90,60,45)=22325=180  t=LCM(a,b,c)=LCM(90,60,45)=180 min



Did you find an error or inaccuracy? Feel free to write us. Thank you!







Tips for related online calculators
Do you want to calculate the least common multiple of two or more numbers?
Do you want to convert time units like minutes to seconds?

You need to know the following knowledge to solve this word math problem:

Related math problems and questions: