# Wall height

Calculate the surface and volume of a regular quadrangular pyramid if side a = 6 cm and wall height v = 0.8dm.

Correct result:

S =  132 cm2
V =  88.994 cm3

#### Solution:

$h=\sqrt{ v^2-(a/2)^2 }=\sqrt{ 8^2-(6/2)^2 } \doteq \sqrt{ 55 } \doteq 7.4162 \ \\ V=S_{1} \cdot \ h/3=36 \cdot \ 7.4162/3=12 \ \sqrt{ 55 }=88.994 \ \text{cm}^3$

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