Wall height

Calculate the surface and volume of a regular quadrangular pyramid if side a = 6 cm and wall height v = 0.8dm.

Correct result:

S =  132 cm2
V =  88.9944 cm3

Solution:

a=6 v=0.8⋅ 10=8 S1=a2=62=36 S2=a⋅ v/2=6⋅ 8/2=24 S=S1+4⋅ S2=36+4⋅ 24=132 cm2
h=v2−(a/2)2=82−(6/2)2=55≐7.4162 V=S1⋅ h/3=36⋅ 7.4162/3=12 55=88.9944 cm3

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