Prism bases

Volume perpendicular quadrilateral prism is 360 cm3. The edges of the base and height of the prism are in the ratio 5:4:2 Determine the area of the base and walls of the prism.

Result

S1 =  86.535 cm2
S2 =  34.614 cm2
S3 =  43.267 cm2

Solution:

V=360 a:b:c=5:4:2 V=abc=5⋅ 4⋅ 2⋅ k3 k=V/(5⋅ 4⋅ 2)3=360/(5⋅ 4⋅ 2)3≐2.0801 a=5⋅ k=5⋅ 2.0801≐10.4004 b=4⋅ k=4⋅ 2.0801≐8.3203 c=2⋅ k=2⋅ 2.0801≐4.1602 S1=a⋅ b=10.4004⋅ 8.3203≐86.535≐86.535 cm2V=360 \ \\ a:b:c=5:4:2 \ \\ V=abc=5 \cdot \ 4 \cdot \ 2 \cdot \ k^3 \ \\ k=\sqrt[3]{ V/(5 \cdot \ 4 \cdot \ 2)}=\sqrt[3]{ 360/(5 \cdot \ 4 \cdot \ 2)} \doteq 2.0801 \ \\ a=5 \cdot \ k=5 \cdot \ 2.0801 \doteq 10.4004 \ \\ b=4 \cdot \ k=4 \cdot \ 2.0801 \doteq 8.3203 \ \\ c=2 \cdot \ k=2 \cdot \ 2.0801 \doteq 4.1602 \ \\ S_{1}=a \cdot \ b=10.4004 \cdot \ 8.3203 \doteq 86.535 \doteq 86.535 \ \text{cm}^2
S2=b⋅ c=8.3203⋅ 4.1602≐34.614≐34.614 cm2S_{2}=b \cdot \ c=8.3203 \cdot \ 4.1602 \doteq 34.614 \doteq 34.614 \ \text{cm}^2
S3=c⋅ a=4.1602⋅ 10.4004≐43.2675≐43.267 cm2S_{3}=c \cdot \ a=4.1602 \cdot \ 10.4004 \doteq 43.2675 \doteq 43.267 \ \text{cm}^2

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