Bearing

A plane flew 50 km on a bearing 63°20' and the flew on a bearing 153°20' for 140km. Find the distance between the starting point and the ending point.

Correct result:

s =  148.6607 km

Solution:

A=63+20/60=190363.3333 B=153+20/60=4603153.3333 x1=50 cosA=50 cos63.3333333333 =50 0.448799=22.43996 y1=50 sinA=50 sin63.3333333333 =50 0.893633=44.68163 x2=140 cosB=140 cos153.333333333 =140 (0.893633)=125.10857=(229422π/5761) y2=140 sinB=140 sin153.333333333 =140 0.448799=62.83189 x=x1+x2=22.44+(125.1086)102.6686 km y=y1+y2=44.6816+62.8319107.5135 km s=x2+y2=(102.6686)2+107.51352=10 221=148.6607 km



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