Bearing

A plane flew 50 km on a bearing 63°20' and the flew on a bearing 153°20' for 140km. Find the distance between the starting point and the ending point.

Correct result:

s =  148.6607 km

Solution:

A=63+20/60=190363.3333 B=153+20/60=4603153.3333 x1=50 cosA=50 cos63.333333333333 =50 0.448799=22.43996 km y1=50 sinA=50 sin63.333333333333 =50 0.893633=44.68163 km x2=140 cosB=140 cos153.33333333333 =140 (0.893633)=125.10857=(229422π/5761) km y2=140 sinB=140 sin153.33333333333 =140 0.448799=62.83189 km x=x1+x2=22.44+(125.1086)102.6686 km y=y1+y2=44.6816+62.8319107.5135 km s=x2+y2=(102.6686)2+107.51352=10 221=148.6607 km



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Tips to related online calculators
For Basic calculations in analytic geometry is a helpful line slope calculator. From coordinates of two points in the plane it calculate slope, normal and parametric line equation(s), slope, directional angle, direction vector, the length of segment, intersections the coordinate axes etc.
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See also our trigonometric triangle calculator.

 
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