Bearing

A plane flew 50 km on a bearing 63°20' and the flew on a bearing 153°20' for 140km. Find the distance between the starting point and the ending point.

Correct answer:

s =  148.6607 km

Step-by-step explanation:

A=636020=63+6020=6063 60+20=603800=319063.3333  B=1536020=153+6020=60153 60+20=609200=3460153.3333  a=50 km b=140 km  x1=a cosA=a cos63.333333333333° =50 cos63.333333333333° =50 0.448799=22.43996 km y1=a sinA=a sin63.333333333333° =50 sin63.333333333333° =50 0.893633=44.68163 km x2=b cosB=b cos153.33333333333° =140 cos153.33333333333° =140 (0.893633)=125.10857=(229422π/5761) km y2=b sinB=b sin153.33333333333° =140 sin153.33333333333° =140 0.448799=62.83189 km x=x1+x2=22.44+(125.1086)102.6686 km y=y1+y2=44.6816+62.8319107.5135 km s=x2+y2=(102.6686)2+107.51352=10 221=148.6607 km



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