Plane II

A plane flew 50 km on a bearing of 63°20' and then flew in the direction of 153°20' for 140km. Find the distance between the starting point and the ending point.

Correct answer:

x =  148.6607 km

Step-by-step explanation:

α=63°20=63°+6020°=63.3333°63.3333 β=153°20=153°+6020°=153.3333°153.3333 γ=βα=153.333363.3333=90   a=50 km b=140 km  x=a2+b2=502+1402=10 221=148.6607 km

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