Plane II

A plane flew 50 km on a bearing 63degrees20, and the flew on a bearing 153degrees20 for 140km. Find the distance between the starting point and the ending point.

Correct answer:

x =  148.6607 km

Step-by-step explanation:

$$\begin{gathered} u=153+20\mathrm{/}60-(63+20\mathrm{/}60)=90 \\ x=\sqrt{50^2+140^2}=10\sqrt{221}=148.6607\text{ km} \end{gathered}$$

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