Cuboid surface

Determine surface area of cuboid if its volume is 52.8 cm cubic and length of the two edges are 2 cm and 6 cm.

Result

S =  94.4 cm2

Solution:

V=52.8 a=2 b=6 S1=a b=2 6=12 c=V/S1=52.8/12=225=4.4 S=2 S1+2 c (a+b)=2 12+2 4.4 (2+6)=4725=94.4=94.4 cm2V = 52.8 \ \\ a = 2 \ \\ b = 6 \ \\ S_{ 1 } = a \cdot \ b = 2 \cdot \ 6 = 12 \ \\ c = V/S_{ 1 } = 52.8/12 = \dfrac{ 22 }{ 5 } = 4.4 \ \\ S = 2 \cdot \ S_{ 1 } +2 \cdot \ c \cdot \ (a+b) = 2 \cdot \ 12 +2 \cdot \ 4.4 \cdot \ (2+6) = \dfrac{ 472 }{ 5 } = 94.4 = 94.4 \ cm^2



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