Cuboid surface

Determine surface area of cuboid if its volume is 52.8 cm cubic and length of the two edges are 2 cm and 6 cm.

Correct result:

S =  94.4 cm2

Solution:

V=52.8 a=2 b=6 S1=a⋅ b=2⋅ 6=12 c=V/S1=52.8/12=225=4.4 S=2⋅ S1+2⋅ c⋅ (a+b)=2⋅ 12+2⋅ 4.4⋅ (2+6)=4725=94.4 cm2V=52.8 \ \\ a=2 \ \\ b=6 \ \\ S_{1}=a \cdot \ b=2 \cdot \ 6=12 \ \\ c=V/S_{1}=52.8/12=\dfrac{ 22 }{ 5 }=4.4 \ \\ S=2 \cdot \ S_{1} +2 \cdot \ c \cdot \ (a+b)=2 \cdot \ 12 +2 \cdot \ 4.4 \cdot \ (2+6)=\dfrac{ 472 }{ 5 }=94.4 \ \text{cm}^2

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