Surface of cuboid

Find the surface of the cuboid if its volume is 52.8 cm3 and the length of its two edges is 2 cm and 6 cm.

Result

S =  94.4 cm2

Solution:

V=52.8 cm3 a=2 cm b=6 cm S1=a⋅ b=2⋅ 6=12 cm2 c=V/S1=52.8/12=225=4.4 cm S=2⋅ (S1+b⋅ c+a⋅ c)=2⋅ (12+6⋅ 4.4+2⋅ 4.4)=4725=94.4 cm2V=52.8 \ \text{cm}^3 \ \\ a=2 \ \text{cm} \ \\ b=6 \ \text{cm} \ \\ S_{1}=a \cdot \ b=2 \cdot \ 6=12 \ \text{cm}^2 \ \\ c=V / S_{1}=52.8 / 12=\dfrac{ 22 }{ 5 }=4.4 \ \text{cm} \ \\ S=2 \cdot \ (S_{1} + b \cdot \ c + a \cdot \ c)=2 \cdot \ (12 + 6 \cdot \ 4.4 + 2 \cdot \ 4.4)=\dfrac{ 472 }{ 5 }=94.4 \ \text{cm}^2

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