Octahedron - sum

On each wall of a regular octahedron is written one of the numbers 1, 2, 3, 4, 5, 6, 7 and 8, wherein on different sides are different numbers. For each wall John make the sum of the numbers written of three adjacent walls. Thus got eight sums, which also added up.
What values the resulting sum may have?

Result

s =  144

Solution:

s1=1+2+3+4+5+6+7+8=36 s=4⋅ s1=4⋅ 36=144s_{1}=1+2+3+4+5+6+7+8=36 \ \\ s=4 \cdot \ s_{1}=4 \cdot \ 36=144

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