# Wiring

Conduit has a cross section 482 mm. Maybe put it into 6 conductors with a cross section S2 \$mm2?

Result

#### Solution:

$r_1 = \sqrt{ \dfrac{ 48}{ \pi}} = 3.91 \ \text{mm} \ \\ r_2 = \sqrt{ \dfrac{ 5.4}{ \pi}} = 1.31 \ \text{mm} \ \\ \ \\ 2\cdot r_1 < 6 \cdot r_2 \ \\$

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