Wiring

Conduit has a cross section 482 mm. Maybe put it into 6 conductors with a cross section S2 $mm2?

Result




Solution:

r1=48π=3.91 mm r2=5.4π=1.31 mm  2r1<6r2 r_1 = \sqrt{ \dfrac{ 48}{ \pi}} = 3.91 \ \text{mm} \ \\ r_2 = \sqrt{ \dfrac{ 5.4}{ \pi}} = 1.31 \ \text{mm} \ \\ \ \\ 2\cdot r_1 < 6 \cdot r_2 \ \\



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