# Pool

If water flows into the pool by two inlets, fill the whole for 20 hours. The first inlet filled the pool 8 hour longer than the second. How long does the pool take to fill with two inlets separately?

## Correct answer:

**Showing 3 comments:**

**Math student**

1/t1+1/(t1-10)=1/18

multiply each term by18(t1)(t1-10)

that results in

18(t1-10)+18t1=t1(t1)(t1)-10t1

using the quadratic formula results in t1=-49.6 and 3.63

ubless i made a mistake, your calculations need reexamination!!! Correct me, please.

multiply each term by18(t1)(t1-10)

that results in

18(t1-10)+18t1=t1(t1)(t1)-10t1

using the quadratic formula results in t1=-49.6 and 3.63

ubless i made a mistake, your calculations need reexamination!!! Correct me, please.

5 years ago 4 Likes

**Dr Math**

right side of equation is wrong - should be t1*(t1-10) = t1

^{2}- 10*t1 now t1^{3}-10t1
5 years ago 1 Like

**Math student**

the problems seems to have changed - - - t2 is now equal t1-6

therefore 1/t1+1/(t1-6)=1/18

multiplying each term by18(t1)(t1-6) ==== 18(t1-6)+18t1=t1(t1-6), simplifying further 18t1-108+18t1=t1

or 0=t1

graphing y=18(t1-6)+18t1-t1(t1-6) results in t1=39.25 hours and t2=39.25-6=33.25 hours (same as your NEW answer!!!!

therefore 1/t1+1/(t1-6)=1/18

multiplying each term by18(t1)(t1-6) ==== 18(t1-6)+18t1=t1(t1-6), simplifying further 18t1-108+18t1=t1

^{2}-6t1or 0=t1

^{2}-6t1-18t1+108graphing y=18(t1-6)+18t1-t1(t1-6) results in t1=39.25 hours and t2=39.25-6=33.25 hours (same as your NEW answer!!!!

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### You need to know the following knowledge to solve this word math problem:

**statistics**- harmonic mean
**algebra**- quadratic equation
- equation
- system of equations
**arithmetic**- square root
- square (second power, quadratic)
- exponentiation
**basic functions**- reason
- inverse relationship
- direct relationship
**numbers**- fractions
- real numbers

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