Pool

Water flows into a pool through two inlets and fills it in 5 hours. If the first inlet alone takes 5 hours longer than the second inlet alone, how long does each inlet take to fill the pool on its own?

Final Answer:

t1 =  13.09 h
t2 =  8.09 h

Step-by-step explanation:

t11+t21 = 51 t1 = t2 + 5 h  t2 = t1  5 1/t1 + 1/(t15) = 1/5  5 (x5)+5 x=(x5) x  5 (x5)+5 x=(x5) x x2+15x25=0 x215x+25=0  a=1;b=15;c=25 D=b24ac=1524125=125 D>0  x1,2=2ab±D=215±125=215±55 x1,2=7.5±5.59017 x1=13.090169944 x2=1.909830056  t1>0 t1=x1=13.0902=13.09 h

Our quadratic equation calculator calculates it.

t2>0 t2=t15=13.09025=8.09 h



Help us improve the example. If you find a mistake, let us know. Thank you!



Showing 3 comments:
Math student
1/t1+1/(t1-10)=1/18
multiply each term by18(t1)(t1-10)
that results in
18(t1-10)+18t1=t1(t1)(t1)-10t1
using the quadratic formula results in t1=-49.6 and 3.63
ubless i made a mistake, your calculations need reexamination!!!        Correct me, please.

7 years ago  4 Likes
Dr Math
right side of equation is wrong - should be t1*(t1-10) = t12 - 10*t1 now t13-10t1

7 years ago  1 Like
Math student
the problems seems to have changed - - - t2 is now equal t1-6

therefore 1/t1+1/(t1-6)=1/18
multiplying each term by18(t1)(t1-6) ==== 18(t1-6)+18t1=t1(t1-6), simplifying further 18t1-108+18t1=t12-6t1
or 0=t12-6t1-18t1+108
graphing y=18(t1-6)+18t1-t1(t1-6) results in t1=39.25 hours and t2=39.25-6=33.25 hours (same as your NEW answer!!!!





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