School

Headteacher think whether the distribution of pupils in race in groups of 4,5,6,9 or 10. How many pupils must have at least school at possible options?

Result

x =  180

Solution:

4=22 5 ... primenumber 6=2⋅3 9=32 10=2⋅5 LCM(4,5,6,9,10)=22⋅32⋅5=180  x=LCM(4,5,6,9,10)=1804=2^2 \ \\ 5 \ ... \ prime number \ \\ 6=2 \cdot 3 \ \\ 9=3^2 \ \\ 10=2 \cdot 5 \ \\ LCM(4, 5, 6, 9, 10)=2^2 \cdot 3^2 \cdot 5=180 \ \\ \ \\ x=LCM(4,5,6,9,10)=180

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