Ladder

4 m long ladder touches the cube 1mx1m at the wall. How high reach on the wall?

Correct result:

q₁ =  1.3622 m
q₂ =  3.7609 m

Solution:

$$\begin{gathered} k_2=1\mathrm{/}(1-x_{02})=1\mathrm{/}(1-1.3622)\doteq -2.7609 \\ {q}_2=1-k_2=1-(-2.7609)\doteq 3.7609=3.7609\text{ m } \\ {l}_2=\sqrt{q_2^2+x_{02}^2}=\sqrt{3.7609^2+1.3622^2}=4 \end{gathered}$$

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