Numbers

Determine the number of all positive integers less than 4183444 if each is divisible by 29, 7, 17.

What is its sum?

Correct result:

n =  1212
S =  2536754178

Solution:

a1=29⋅7⋅17=3451  n=⌊4183444a1⌋=1212
S=n2(a1+an)=n2(a1+na1)=n(n+1)2⋅a1=2536754178

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