Numbers

Determine the number of all positive integers less than 4183444 if each is divisible by 29, 7, 17.

What is its sum?

Correct result:

n =  1212
S =  2536754178

Solution:

$S=\frac{n}{2}\left({a}_{1}+{a}_{n}\right)=\frac{n}{2}\left({a}_{1}+n{a}_{1}\right)=\frac{n\left(n+1\right)}{2}\cdot {a}_{1}=2536754178$

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