Diagonals of diamond

Find the area and circumference of the diamond ABCD with 15m and 11m diagonals.

Correct result:

S =  82.5 m2
o =  37.202 m

Solution:

u1=15 m u2=11 m S=u1 u22=15 112=1652=82.5 m2
a=(u1/2)2+(u2/2)2=(15/2)2+(11/2)29.3005 m o=4 a=4 9.3005=2 346=37.202 ma=\sqrt{ (u_{1}/2)^2+(u_{2}/2)^2 }=\sqrt{ (15/2)^2+(11/2)^2 } \doteq 9.3005 \ \text{m} \ \\ o=4 \cdot \ a=4 \cdot \ 9.3005=2 \ \sqrt{ 346 }=37.202 \ \text{m}



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Pythagorean theorem is the base for the right triangle calculator.
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