Dimensions 4700

The toolbox has internal dimensions, a length of 1.5 meters, a width of 80 cm, and a height of 6 dm. Calculate the longest rod we can hide in this box.

Final Answer:

x =  18.0278 dm

Step-by-step explanation:

$$\begin{gathered} a=1.5\text{m}\to \text{dm}=1.5\cdot 10\text{dm}=15\text{dm} \\ b=80\text{cm}\to \text{dm}=80:10\text{dm}=8\text{dm} \\ c=6\text{dm} \\ {x}^2=a^2+b^2+c^2 \\ x=\sqrt{a^2+b^2+c^2}=\sqrt{15^2+8^2+6^2}=5\sqrt{13}=18.0278\text{dm} \end{gathered}$$

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