# Cuboidal room

Length of cuboidal room is 2m
breadth of cuboidal room is 3m
and height is 6m
find the length of the longest rod that can be fitted in the room

Result

d =  7 m

#### Solution:

$a = 2 \ m \ \\ b = 3 \ m \ \\ c = 6 \ m \ \\ \ \\ d = \sqrt{ a^2+b^2+c^2 } = \sqrt{ 2^2+3^2+6^2 } = 7 = 7 \ \text{ m }$

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