Parallelogram ABCD

We have the parallelogram ABCD, where AB is 6.2 cm
BC is 5.4 cm
AC is 4.8 cm
calculate the height on the AB side and the angle DAB

Correct answer:

v =  4.0307 cm
A =  36.7385 °

Step-by-step explanation:

a=6.2 cm b=5.4 cm u=4.8 cm  s=2a+b+u​=26.2+5.4+4.8​=541​=8.2 cm S1​=s⋅ (s−a)⋅ (s−b)⋅ (s−u)​=8.2⋅ (8.2−6.2)⋅ (8.2−5.4)⋅ (8.2−4.8)​≐12.4951 cm2  S=2⋅ S1​=2⋅ 12.4951≐24.9902 cm2  S = a⋅ v  v=S/a=24.9902/6.2=4.0307 cm
tanA=v:b=4.0307:5.4≐0.7464=52010:69679  α=arctan(v/b)=arctan(4.0307/5.4)≐0.6412 rad A=α→  °=α⋅ π180​   °=0.6412⋅ π180​   °=36.739  °=36.7385∘=36°44′19"

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algebraplanimetricsgoniometry and trigonometryUnits of physical quantitiesGrade of the word problem

 
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