How far must Paul place a mirror to see the top of the tower 12 m high? The height of Paul's eyes above the horizontal plane is 160 cm and Paul is from the tower distant 20 m.

Correct result:

x =  2.3529 m


a=160/100=85=1.6 m x=20/(12+a) a=20/(12+1.6) 1.6=4017=2.3529 m

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