Body diagonal

Cuboid with base 7cm x 3,9cm and body diagonal 9cm long. Find the height of the cuboid and the length of the diagonal of the base,

Result

u1 =  8.013 cm
h =  4.098 cm

Solution:

a=7 cm b=3.9 cm u=9 cm u1=u1=a2+b2≐72+3.92≐8.0131≐8.013 cma=7 \ \text{cm} \ \\ b=3.9 \ \text{cm} \ \\ u=9 \ \text{cm} \ \\ u_{1}=u_{ 1 }=\sqrt{ a^2+b^2 } \doteq \sqrt{ 7^2+3.9^2 } \doteq 8.0131 \doteq 8.013 \ \text{cm}
h=u2−u12=92−8.01312≐4.0978≐4.098 cmh=\sqrt{ u^2-u_{ 1 }^2 }=\sqrt{ 9^2-8.0131^2 } \doteq 4.0978 \doteq 4.098 \ \text{cm}

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