Concrete block

Determine the volume of concrete block whose one edge of the base has a length 3 meters, body diagonal is 13 meters and its height is 12 meters.

Result

V =  144 m3

Solution:

a=3 t=13 c=12 s=t2c2=132122=5 b=s2a2=5232=4 V=a b c=3 4 12=144=144 m3a = 3 \ \\ t = 13 \ \\ c = 12 \ \\ s = \sqrt{ t^2-c^2 } = \sqrt{ 13^2-12^2 } = 5 \ \\ b = \sqrt{ s^2-a^2 } = \sqrt{ 5^2-3^2 } = 4 \ \\ V = a \cdot \ b \cdot \ c = 3 \cdot \ 4 \cdot \ 12 = 144 = 144 \ m^3



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