Tangent 3

In a circle with centre O radius is 4√5 cm. EC is the tangent to the circle at point D. Segment AB IS THE DIAMETER of given circle. POINT A is joined with POINT E and POINT B is joined with POINT C. Find DC if BC IS 8cm.

Correct result:

x =  NAN cm

Solution:

$$\begin{gathered} r=4\cdot \sqrt{5}=4\sqrt{5}\text{ cm}\doteq 8.9443\text{ cm } \\ c=8\text{ cm } \\ x=r+\sqrt{c^2-r^2}=8.9443+\sqrt{8^2-8.9443^2}=NAN\text{ cm} \end{gathered}$$

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Showing 3 comments:

Matikar

Problem has no solution because  r > c

2 years ago  Like

Math student

Hey I can't get this coz I never started this yet

2 years ago  Like

Math student

I can't understand it plz get another example

2 years ago  Like

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