# Tangent 3

In a circle with centre O radius is 4√5 cm. EC is the tangent to the circle at point D. Segment AB IS THE DIAMETER of given circle. POINT A is joined with POINT E and POINT B is joined with POINT C. Find DC if BC IS 8cm.

Correct result:

x =  NAN cm

#### Solution:

$r=4 \cdot \ \sqrt{ 5 }=4 \ \sqrt{ 5 } \ \text{cm} \doteq 8.9443 \ \text{cm} \ \\ c=8 \ \text{cm} \ \\ x=r + \sqrt{ c^2 - r^2 }=8.9443 + \sqrt{ 8^2 - 8.9443^2 }=NAN \ \text{cm}$

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Matikar
Problem has no solution because  r > c

Math student
Hey I can't get this coz I never started this yet

Math student
I can't understand it plz get another example

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