TV fail

The TV has after 10,000 hours average 25 failures. Determine the probability of TV failure after 200 hours of operation.

Result

p =  39.38 %

Solution:

p=100(1(12510000)200)=39.38%p = 100\cdot \left(1- (1- \dfrac{ 25}{ 10000})^{ 200}\right) = 39.38 \%



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