Two workers

Two workers should fulfill specific tasks together for five days. If the first worker increased their performance twice and the second twice fell, it took them just four days. For how many days would he handle the entire task, the first worker himself?

Correct answer:

a =  10 d

Step-by-step explanation:

1/a+1/b = 1/5 2/a+1/(2b)=1/4  1/b = 1/5  1/a 2/a+0.5 (1/51/a) = 1/4 2 + 0.5 (1/5a1) = 1/4a 1.5 + 1/10a = 1/4a a=1.5/(1/41/10)=10=10 d b=1/(1/51/a)=1/(1/51/10)=10 d



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