Two workers

Two workers should fulfill specific tasks together for five days. If the first worker increased their performance twice and the second twice fell, it took them just four days. For how many days would he handle the entire task, the first worker himself?

Final Answer:

a =  10 d

Step-by-step explanation:

1/a+1/b = 1/5 2/a+1/(2b)=1/4  1/b = 1/5  1/a 2/a+0.5 (1/51/a) = 1/4 2 + 0.5 (1/5a1) = 1/4a 1.5 + 1/10a = 1/4a a=1.5/(1/41/10)=10=10 d b=1/(1/51/a)=1/(1/51/10)=10 d



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You need to know the following knowledge to solve this word math problem:

algebrabasic operations and conceptsUnits of physical quantitiesthemes, topicsGrade of the word problem

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