Possibilities 5822

Peter forgot the four-digit code to his school locker lock. Fortunately, his mother remembered some information about him. He knows that the first binary number is divisible by 15 and the second by 7. However, Peter is a big loser, so he has to try all the possibilities (including the possibility of 0000). How many attempts did Peter take to open the lock?

Correct answer:

n =  105

Step-by-step explanation:

n1 = 0000 n2 = 0007 n3 = 0014 n4 = 0021 n5 = 0028 n6 = 0035 n7 = 0042 n8 = 0049 n9 = 0056 n10 = 0063 n11 = 0070 n12 = 0077 n13 = 0084 n14 = 0091 n15 = 0098 n16 = 1500 n17 = 1507 n18 = 1514 n19 = 1521 n20 = 1528 n21 = 1535 n22 = 1542 n23 = 1549 n24 = 1556 n25 = 1563 n26 = 1570 n27 = 1577 n28 = 1584 n29 = 1591 n30 = 1598 n31 = 3000 n32 = 3007 n33 = 3014 n34 = 3021 n35 = 3028 n36 = 3035 n37 = 3042 n38 = 3049 n39 = 3056 n40 = 3063 n41 = 3070 n42 = 3077 n43 = 3084 n44 = 3091 n45 = 3098 n46 = 4500 n47 = 4507 n48 = 4514 n49 = 4521 n50 = 4528 n51 = 4535 n52 = 4542 n53 = 4549 n54 = 4556 n55 = 4563 n56 = 4570 n57 = 4577 n58 = 4584 n59 = 4591 n60 = 4598 n61 = 6000 n62 = 6007 n63 = 6014 n64 = 6021 n65 = 6028 n66 = 6035 n67 = 6042 n68 = 6049 n69 = 6056 n70 = 6063 n71 = 6070 n72 = 6077 n73 = 6084 n74 = 6091 n75 = 6098 n76 = 7500 n77 = 7507 n78 = 7514 n79 = 7521 n80 = 7528 n81 = 7535 n82 = 7542 n83 = 7549 n84 = 7556 n85 = 7563 n86 = 7570 n87 = 7577 n88 = 7584 n89 = 7591 n90 = 7598 n91 = 9000 n92 = 9007 n93 = 9014 n94 = 9021 n95 = 9028 n96 = 9035 n97 = 9042 n98 = 9049 n99 = 9056 n100 = 9063 n101 = 9070 n102 = 9077 n103 = 9084 n104 = 9091 n105 = 9098 n=15 7=105



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