Locker combination

Todd forgot the first two numbers of his locker combination. The numbers can be any number 1 through 6. What is the probability that he will guess the first number correctly and the second number incorrectly?

Final Answer:

p =  5/36

Step-by-step explanation:

$$\begin{gathered} p_1=\frac{1}{6}\doteq 0.1667 \\ {p}_2=\frac{5}{6}\doteq 0.8333 \\ p=p_1\cdot p_2=\frac{1}{6}\cdot \frac{5}{6}=\frac{1\cdot 5}{6\cdot 6}=\frac{5}{36}=0.1389 \end{gathered}$$

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