Recurrence relation

Consider a recurrence relation an = 3an-1 - 3an-2 for n = 1,2,3,4,… with initial conditions a1 = 4 and a2 = 2. Calculate a5.

Correct answer:

a5 =  -54

Step-by-step explanation:

a1=4 a2=2  a(n) = 3a(n1)  3a(n2)  a3=3 a23 a1=3 23 4=6 a4=3 a33 a2=3 (6)3 2=24 a5=3 a43 a3=3 (24)3 (6)=54



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