A particle 2

If the motion of a particle is described by the relation a(t) = 7t3 + 2 m/s2, and the initial velocity of the motion is zero when t = 0 and the distance is 2m, t = 0.5s. Determine the velocity and displacement when t = 10s.

Correct answer:

v =  17520 m/s

Step-by-step explanation:

a(t) = 7t3 + 2 m/s2 v(0)=0  m/s x(0)=0  m  x(0.5)=2  m  t2=10 s  a(t) = d v(t) / dt  integrate: v(t) = 7   t4/4 + 2 t + c1 v(0) = 7   04/4 + 2 0 + c1 = 0 c1=0 v(t) = 1.75   t4 + 2 t  x(t) = 7  4 5t5 + 2 t2/2 + c2  v=1.75 t24+2 t2=1.75 104+2 10=17520 m/s



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