Acceleration 82397

The position of a mass point that moves along the x-axis is given by the relation x=10t2-5t. Express its velocity and acceleration.

Correct answer:

v = 20t-5
a =  20

Step-by-step explanation:

x=10t25t v = x =ΔtΔx=  d td x  v = 10 2 t5 v=20t5
a=v=ΔtΔv=  d td v a=20 1=20



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