Circular motion

Mass point moves moves uniformly in a circle with radius r = 3.4 m angular velocity ω = 3.6 rad/s. Calculate the period, frequency, and the centripetal acceleration of this movement.

Correct result:

T =  1.75 s
f =  0.57 Hz
a =  44.06 m/s²

Solution:

$$\begin{gathered} \omega =2\pi f \\ f=1\mathrm{/}T \\ T={\displaystyle \frac{2\pi }{3.6}}=1.75\text{ s} \end{gathered}$$

$f=1\mathrm{/}T=0.57\text{ Hz}$

$a=r{\omega }^2=3.4\cdot 3.6^2=44.06{\text{m/s}}^2$

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