Warehouses

To four warehouses is going cement in 25 kg bags. To first one third, to second quarter of the total. The third store got two thirds of the rest, and the last 310 tons came to fourth. How many cement is in all warehouses and how much got every one?

Correct result:

t (total) =  2232 ton
m1 =  744 ton
m2 =  558 ton
m3 =  620 ton
m4 =  310 ton

Solution:

m1+m2+m3+m4=t t3+t4+23(tt3+t4)+310=t 536t=310 t=2232 tonm_1+m_2 + m_3 + m_4 = t \ \\ \dfrac{t}{3} + \dfrac{t}{4} + \dfrac{2}{3}(t-\dfrac{t}{3} + \dfrac{t}{4}) + 310 = t \ \\ \dfrac{5}{36} t = 310 \ \\ t= 2232 \ \text{ton}
m1=t3=744 tonm_1 = \dfrac{t}{3} = 744 \ \text{ton}
m2=t4=558 tonm_2 = \dfrac{t}{4} = 558 \ \text{ton}
m3=512t=620 tonm_3 = \dfrac{5}{12}t = 620 \ \text{ton}
m4=310 tonm_4 = 310 \ \text{ton}



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