Inscribed circle

Calculate the magnitude of the BAC angle in the triangle ABC if you know that it is 3 times less than the angle BOC, where O is the center of the circle inscribed in the triangle ABC.

Result

A =  36 °

Solution:

A+B+C=180 A=O/3 C/2+O+B/2=180 C/2+P+A/2=180 B/2+Q+A/2=180 B=rand(1...120)  O=108 ∘ A=O/3=108/3=36=36∘A+B+C = 180 \ \\ A = O/3 \ \\ C/2+O+B/2 = 180 \ \\ C/2+P+A/2 = 180 \ \\ B/2+Q+A/2 = 180 \ \\ B = rand(1...120) \ \\ \ \\ O = 108 \ ^\circ \ \\ A = O/3 = 108/3 = 36 = 36 ^\circ

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