Lengths 63174

The block has a square base of 36 dm², and its height is 1/3 of the length of the base edge. Find the sum of the lengths of all edges of a block.

Correct answer:

x =  56 dm

Step-by-step explanation:

$$\begin{gathered} S_1=36{\text{dm}}^2 \\ {S}_1=a^2 \\ a=\sqrt{S_1}=\sqrt{36}=6\text{dm} \\ c=\frac{1}{3}\cdot a=\frac{1}{3}\cdot 6=\frac{1\cdot 6}{3}=\frac{6}{3}=2\text{dm} \\ x=8\cdot a+4\cdot c=8\cdot 6+4\cdot 2=56\text{dm} \end{gathered}$$

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