# Pairs

At the table sit 10 people, 5 on one side and 5 on the other side. Among them are 3 pairs. Every pair wants to sit opposite each other.

How many ways can they sit?

Result

n =  11520

#### Solution:

$n = (2 \cdot 5) \cdot (2 \cdot 4) \cdot (2 \cdot 3)\cdot (10-2\cdot 3)! = 11520$ Our examples were largely sent or created by pupils and students themselves. Therefore, we would be pleased if you could send us any errors you found, spelling mistakes, or rephasing the example. Thank you!

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super dude Tips to related online calculators
Would you like to compute count of combinations?

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