# Equilateral triangle

How long should be the minimum radius of the circular plate to be cut equilateral triangle with side 19 cm from it?

Result

r =  10.97 cm

#### Solution:

$\ \\ \sin(60 ^\circ ) = \dfrac{ 19/2 }{r } \ \\ r = \dfrac{ 19/2 }{ \sin(60 ^\circ ) } \ \\ \ \\ r \doteq 10.97 \ \text{cm}$

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