# Right triangle

Calculate the length of the remaining two sides and the angles in the rectangular triangle ABC if a = 10 cm, angle alpha = 18°40'.

Correct result:

A =  18.667 °
B =  71.333 °
C =  90 °
a =  10 cm
b =  29.6 cm
c =  31.244 cm

#### Solution:

$A=18+40\mathrm{/}60=\frac{56}{3}=18.66{7}^{\circ }=1{8}^{\circ }4{0}^{\mathrm{\prime }}$
$B=90-A=90-18.6667=71.33{3}^{\circ }=7{1}^{\circ }1{9}^{\mathrm{\prime }}59\mathrm{"}$
$C=90=9{0}^{\circ }$

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